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Find the value of : ""^(50)C(47)...

Find the value of :
` ""^(50)C_(47)`

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To find the value of \( \binom{50}{47} \), we will use the formula for combinations, which is given by: \[ nCr = \frac{n!}{r!(n-r)!} \] ### Step-by-Step Solution: 1. **Identify the values of n and r**: Here, \( n = 50 \) and \( r = 47 \). 2. **Apply the combination formula**: Using the formula, we have: \[ \binom{50}{47} = \frac{50!}{47!(50-47)!} = \frac{50!}{47! \cdot 3!} \] 3. **Simplify the factorials**: We can express \( 50! \) as: \[ 50! = 50 \times 49 \times 48 \times 47! \] Therefore, substituting this back into our equation gives: \[ \binom{50}{47} = \frac{50 \times 49 \times 48 \times 47!}{47! \cdot 3!} \] 4. **Cancel out the \( 47! \)**: The \( 47! \) in the numerator and denominator cancels out: \[ \binom{50}{47} = \frac{50 \times 49 \times 48}{3!} \] 5. **Calculate \( 3! \)**: We know that: \[ 3! = 3 \times 2 \times 1 = 6 \] 6. **Substitute \( 3! \) back into the equation**: Thus, we have: \[ \binom{50}{47} = \frac{50 \times 49 \times 48}{6} \] 7. **Perform the multiplication**: First, calculate \( 50 \times 49 \times 48 \): \[ 50 \times 49 = 2450 \] \[ 2450 \times 48 = 117600 \] 8. **Divide by 6**: Now, divide \( 117600 \) by \( 6 \): \[ \frac{117600}{6} = 19600 \] ### Final Answer: Thus, the value of \( \binom{50}{47} \) is \( 19600 \).
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