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Evaluate C(31,26)-C(30,26)...

Evaluate
` C(31,26)-C(30,26)`

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To evaluate \( C(31, 26) - C(30, 26) \), we can use the property of combinations which states: \[ C(n, r) = C(n-1, r) + C(n-1, r-1) \] This property can be rearranged to express \( C(n, r) \) in terms of two other combinations. Specifically, we can say: \[ C(31, 26) = C(30, 26) + C(30, 25) \] Now, substituting this into our original expression: \[ C(31, 26) - C(30, 26) = (C(30, 26) + C(30, 25)) - C(30, 26) \] This simplifies to: \[ C(31, 26) - C(30, 26) = C(30, 25) \] Next, we need to calculate \( C(30, 25) \). The formula for combinations is given by: \[ C(n, r) = \frac{n!}{r!(n-r)!} \] Applying this to \( C(30, 25) \): \[ C(30, 25) = \frac{30!}{25! \cdot (30 - 25)!} = \frac{30!}{25! \cdot 5!} \] Now, we can simplify \( C(30, 25) \): \[ C(30, 25) = \frac{30 \times 29 \times 28 \times 27 \times 26}{5 \times 4 \times 3 \times 2 \times 1} \] Calculating the numerator: \[ 30 \times 29 = 870 \] \[ 870 \times 28 = 24360 \] \[ 24360 \times 27 = 657720 \] \[ 657720 \times 26 = 17153220 \] Now, calculating the denominator: \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] Now we divide the numerator by the denominator: \[ C(30, 25) = \frac{17153136}{120} = 142506 \] Thus, the final answer is: \[ C(31, 26) - C(30, 26) = 142506 \]
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