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In a college team there are 15 players o...

In a college team there are 15 players of whoom 3 are teachers . In how many ways can a team of 11 players be selected so as to include only one teachers

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To solve the problem of selecting a team of 11 players from a group of 15 players, including only one teacher, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Total Players and Teachers:** - Total players = 15 - Total teachers = 3 - Total non-teachers = 15 - 3 = 12 2. **Select One Teacher:** - We need to choose 1 teacher from the 3 available teachers. The number of ways to choose 1 teacher from 3 is given by the combination formula \( \binom{n}{r} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose. - Thus, the number of ways to choose 1 teacher is: \[ \binom{3}{1} = 3 \] 3. **Select the Remaining Players:** - After selecting 1 teacher, we need to choose the remaining players from the non-teachers. Since we are forming a team of 11 players and we have already selected 1 teacher, we need to select 10 players from the 12 non-teachers. - The number of ways to choose 10 players from 12 is: \[ \binom{12}{10} = \binom{12}{2} \quad \text{(using the property } \binom{n}{r} = \binom{n}{n-r}\text{)} \] - Now calculate \( \binom{12}{2} \): \[ \binom{12}{2} = \frac{12!}{2!(12-2)!} = \frac{12 \times 11}{2 \times 1} = 66 \] 4. **Calculate the Total Combinations:** - Now, multiply the number of ways to choose the teacher by the number of ways to choose the non-teachers: \[ \text{Total ways} = \binom{3}{1} \times \binom{12}{10} = 3 \times 66 = 198 \] ### Final Answer: The total number of ways to select a team of 11 players including only one teacher is **198**.
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