Home
Class 11
MATHS
Find the equation of the hyperbola, refe...

Find the equation of the hyperbola, referred to its axes as the axes of coordinates,
Whose transverse and conjugate axes in length respectively 2 and 3,

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the hyperbola whose transverse and conjugate axes are of lengths 2 and 3 respectively, we can follow these steps: ### Step 1: Identify the lengths of the axes The lengths of the transverse and conjugate axes are given as: - Transverse axis = 2 - Conjugate axis = 3 ### Step 2: Relate the lengths to 'a' and 'b' The lengths of the axes are related to 'a' and 'b' as follows: - The length of the transverse axis is \(2a\) - The length of the conjugate axis is \(2b\) From the given lengths: - \(2a = 2\) implies \(a = 1\) - \(2b = 3\) implies \(b = \frac{3}{2}\) ### Step 3: Write the standard form of the hyperbola The standard form of the hyperbola centered at the origin with the transverse axis along the x-axis is given by: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] ### Step 4: Substitute the values of 'a' and 'b' Now substituting \(a = 1\) and \(b = \frac{3}{2}\) into the standard form: - \(a^2 = 1^2 = 1\) - \(b^2 = \left(\frac{3}{2}\right)^2 = \frac{9}{4}\) Thus, the equation becomes: \[ \frac{x^2}{1} - \frac{y^2}{\frac{9}{4}} = 1 \] ### Step 5: Simplify the equation This can be rewritten as: \[ x^2 - \frac{4y^2}{9} = 1 \] ### Step 6: Clear the fraction To eliminate the fraction, multiply through by 9: \[ 9x^2 - 4y^2 = 9 \] ### Final Equation Thus, the equation of the hyperbola is: \[ 9x^2 - 4y^2 = 9 \]
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Find the equation of the hyperbola, referred to its axes as the axes of coordinates, whose conjugate axis is 3 and the distance between whose foci is 5,

Find the equation of the hyperbola, referred to its axes as the axes of coordinates, whose foci are (2,0) and (-2,0) and eccentricity equal to 3/2,

Find the equation of the hyperbola, referred to its axes as the axes of coordinates, the distance between whose foci is 4 and whose eccentricity is sqrt2,

Find the equation to the hyperbola referred to its axes as coordinate axes whose conjugate axis is 7 and passes through the point (3,-2).

Find the equation of the hyperbola, referred to its principal axes as axes of coordinates in the following cases: a. The distance between the foci =16 and eccentricity =sqrt(2) b. Conjugate axis is 5 and the distance between foci =3 c. Conjugate axis is 7 and passes through the point (3,-2).

Find the equation to the ellipse with axes as the axes of coordinates. foci are (pm 4,0) and e=1/3 ,

Find the equation to the ellipse with axes as the axes of coordinates. latus rectum is 5 and eccentricity 2/3 ,

Find the equation to the ellipse with axes as the axes of coordinates. major axis = 6, minor axis = 4,

Find the equation of the hyperbola whole transverse and conjugate axes are 8 and 6 respectively.

Find the equation of the hyperbola, the length of whose latus rectum is 8 , eccentricity is 3/sqrt(5) and whose transverse and conjugate axes are along the x and y axes respectively.