Theorem: The distance between two points `P(x_1;y_1)` and `Q(x_2;y_2)` is given by sqrt((x_2-x_1)^2+(y_2-y_1)^2)

The distance between two points p(x_(1),y_(1)) and q(x_(2),y_(2)) is given be :

The distance between the points p(x_(1),y_(1)) and q(x_(2),y_(2)) given by is :

Find the distance between points P(x_1, y_1) and Q(x_2, y_2) : PQ is parallel to x-axis

Find the distance between points P(x_1, y_1) and Q(x_2, y_2) : PQ is parallel to y-axis

Find the distance between the points P(x_(1),y_(1),z_(1)) and Q(x_(2),y_(2),z_(2))

The co-ordinates of the mid points joining P(x_1,y_1) and Q(x_2,y_2) is….

Prove that the square of the distance between the two points (x_(1), y_(1)) and (x_(2), y_(2)) of the circle x^(2) + y^(2) = a^(2) is 2(a^(2) - x_(1)x_(2) - y_(1)y_(2)) .

Derive the formula for the distance between two points (x_1,y_1,z_1) and (x_2,y_2,z_2) .And hence find the distance between (2,-1,3) and (-2,1,3).

Find the distance between P (x_1,y_1) and Q (x_2,y_2) when PQ is parallel to the y-axis.