Each side of a square substends an angle of `60^@` at the top of a tower h metres h metres high standing in the centre of the square . If a is the length of each side of the square , then

Each side of a square subtends an angle of 60^(@) at the top of a tower 5 meters high standing at the center of the square. If a meters is the length of each side of the square, then a is equal to (use sqrt2=1.41 )

Each side of a square subtends an angle of 60^(@) at the tip of a tower of height h metres standing at the centre of the square. If I is the length of each side of the square, then what is h^(2) equal to ?

Each side of a square ABCD subtends an angle of 60^(@) at the top of a tower of height h standing at the centre of a square.If a be the length of the side of the square,then

Each side of an equilateral triangle subtends an angle of 60^(@) at the top of a tower hm high located at the centre of the triangle. It a is the length of each side of the triangle, then prove that 2a^(2) = 3h^(2) .

Each side of an equilateral triangle subtends angle of 60^(@) at the top of a tower of height h stand centre of the triangle.If 2a be the length of the side of the triangle,then (a^(2))/(h^(2))=

Length of the diagonal of a square is 12 cm. Find the length of each side of the square.