हल कीजिए `(dy)/(dx)=2y, (y gt 0)`.

(dy)/(dx)=2y,(y>0)

"(dy)/(dx)=y^(2)+2y

(dy/dx)+(2/x)y=sinx , x gt 0

If : (dy)/(dx)=(y+3)gt0 and y(0)=2, then : y(-log2)=

Solve the differential equation x (dy )/(dx) - y = 2 x^(3), x gt 0

Solve: (x+3y^2)(dy)/(dx)=y(ygt0)

The solution of the equation (x-4y^3)"dy"/"dx"-y=0, (y gt 0) is

Equation of curve passing through (1, 1) and satisfying the differential equation (dy)/(dx) =(2y) /(x) , ( where x gt 0 , y gt 0 ) is given by :