अवकल समीकरण `(1+y^2)+(x-e^(-tan^(-1))y)(dy)/(dx)=0` को हल कीजिए |

If y=x^(tan ^(-1)x) ,then (dy)/(dx)=

If y=e^((x^(2)+tan y)),(dy)/(dx)=

The solution of differential equation (1+y^(2))+(x-e^(tan^(-1)y))(dy)/(dx)=0 , is

Solve the differential equation: (i) (1+y^(2))+(x-e^( tan ^(-1)y))(dy)/(dx)=0 (ii) x(dy)/(dx)+cos^(2)y=tan y(dy)/(dx)

If y=e^((tan^(-1)x)^(3) then find (dy)/(dx)

Find the general solution of the following differential equation : (1y2)+((x-e^"tan"^((-1_"y")))dy)/(dx)=0

The solution of differential equation (1+y^(2))+((x-2e^(tan^(-1)y))dy)/(dx)=0 is (x-2)=ke^(tan^(-1)y)xe^(tan-1)y=e^(2)tan^(-4)y+kxe^(tan^(-1)y)=tan^(-1)y+kxe^(2tan^(-1)y)=e^(2tan^(-1)y)+k

The solution of the differential equation (1+y^2)+(xe^(tan^-1)y) (dy)/(dx)=0, is (1) (x-2)=ke^(tan^) -1y) (2) 2xe^(2tan^-1y) =e^(2tan^-1y)+k (3) xe^(tan^-1y)=tan^-1y+k (4) xe^(2tan ^-1y)=e^(tan^-1y)+k