`(dy)/(dx)=(x+e^(2x))/(y)`

(dy)/(dx)=(x+e^(x))/(y)

(dy)/(dx)=(x^2+e^(x))/(y)

(dy)/(dx)=(x^2+e^(x))/(y^2)

(dy)/(dx)=(x+e^x)/(y+e^y)

The general solution of (dy)/(dx) = 2x e^(x^(2)-y) is

The solution of the differential equation (dx)/(dy)=(x^(2))/(e^(y)-x)(AA x gt0) is lambdax+2cx^(2)e^(y)=e^(y) (where, c is an arbitrary constant). Then, lambda is euqal to

If e^(x)+e^(y)=e^(x+y), prove that (dy)/(dx)=-(e^(x)(e^(y)-1))/(e^(y)(e^(x)-1)) or,(dy)/(dx)+e^(y-x)=0

e^(y)(dy)/(dx)=e^(x)+x^(2)

Solve the differential equation (dy)/(dx)=e^(2x-y)+x^(2)*e^(-y) .

General solution of (dy)/(dx)=e^(2x-y)+x^(3)e^(-y) is