`int(logx/(1+logx)^2)dx`

int (log x)/(1+logx)^2 dx

Evaluate int[1/logx-1/(logx)^2]dx

int[1/logx-1/(logx)^2]dx= (A) x/logx (B) xlogx (C) logx/x (D) none of these

If int[(logx-1)/(1+(logx)^2)]^2dx=f(x)/(1+(g(x))^2)+c , then (A) f(x)=x (B) f(x)=x^2 (C) g(x)=logx (D) g(x)=(logx)^2

int1/(x(1-logx)^(2))dx=

Evaluate: int1/(xlogxlog(logx))dx

int(logx)/(x(1+logx)(2+logx))dx=

int{(logx-1)/(1+(logx)^(2))}^(2) dx is equal to

"F i n d"int[log(logx)+1/((logx)^2)]dx Find log (log x)+ |dx 2 (log x)