`(dy)/(dx)=xy+2y+x+2`

xy(dy)/(dx)=y+2

Solve: xy(dy)/(dx)=x^2-y^2

The differential equations of all circle touching the x-axis at orgin is (a) (y^(2)-x^(2))=2xy((dy)/(dx)) (b) (x^(2)-y^(2))(dy)/(dx)=2xy ( c ) (x^(2)-y^(2))=2xy((dy)/(dx)) (d) None of these

Solve -x^(2)(dy)/(dx)=2xy+y^(2)

(dy)/(dx)=(2xy)/(x^(2)-y^(2))

2xy(dy)/(dx)=x^(2)+y^(2)

The solution of (dy)/(dx)=2xy-3y+2x-3 is

The solution of the differential equation (dy)/(dx)=(xy)/(x^(2)+y^(2)) is

The function y=f(x) is the solution of the differential equation (dy)/(dx)=(2xy+y^(2))/(2x^(2)) If f(1)=2, then the value of f((1)/(4)) is