A particle is executing SHM about y =0 along y-axis. Its position at an instant is given by `y = (7m) sin (pit)`. Its average velocity for a time interval 0 to 0.5 s is

A particle executes simple harmonic motion about x=0 along x-axis. The position of the particle at an instant is given by x= ( 5 cm) sin pi t . Find the average velocity and average acceleration for a time interval 0-0.5 s . Hint : Average velocity =( x_(2)- x_(1))/(t_(2)-t_(1)) x_(1) = 5 sin 0 x_(2) = 5 sin ( pi xx 0.5) t_(2) - t_(1) = 0.5 Average acceleration = ( v_(2) - v_(1))/( t_(2) - t_(1)) v=(dx)/(dt) = 5 pi cos pit implies a _(av) = ( 5 pi cos ( pi xx 0.5) -5 pi cos theta)/(0.5)

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

For a particle executing SHM along x-axis, force acting on it, is given by (A, k gt 0)

The particle is executing SHM on a line 4 cm long. If its velocity at mean position is 12 m/s , then determine its frequency.

A particle of mass m executing S.H.M. about its mean position. The total energy of the particle at given instant is

A particle of mass m is executing SHM about its mean position. The total energy of the particle at given instant is

Particle executing SHM along y-axis has its motion described by the equation y=2 + 10 sin 5pi d . Amplitude of SHM is

A particle executing SHM along y-axis, which is described by y = 10 "sin"(pi t)/(4) , phase of particle at t =2s is

A particle is executing SHM . It passes through mean position at the instant t = 0 . At what instants the speed of it is 50% of its maximum speed?

The displacement of a particle executing S.H.M from its mean position is given by x = 0.5 sin (10 pit +phi) cos (10pit +phi) . The ratio of the maximum velocity to the maximum acceleration of the body is given by