Electric and magnetic field are directed as `E_(0) hat(i)` and `B_(0) hat(k)`, a particle of mass m and charge + q is released from position (0,2,0) from rest. The velocity of that particle at (x,5,0) is `(5 hat(i) + 12 hat(j))` the value of x will be

Electric field and magnetic field in a region of space are given by (Ē= E_0 hat j) . and (barB = B_0 hat j) . A charge particle is released at origin with velocity (bar v = v_0 hat k) then path of particle is

If a unit vector is represented by 0.5 hat(i) + 0.8 hat(j) + c hat(k) , then the value of c is

In region x gt 0 a uniform and constant magnetic field vec(B)_(1) = 2 B_(0) hat(k) exists. Another uniform and constant magnetic field vec(B)_(2) = B_(0) hat(k) exists in region x lt 0 A positively charged particle of mass m and charge q is crossing origin at time t =0 with a velocity bar(u) = u_(0) hat(i) . The particle comes back to its initial position after a time : ( B_(0),u_(0) are positive constants)

Electric field and magnetic field in a region of space are given by vec E = E_(0) hat I " and " vec B = - B_(0) hat k , respectively. A positively charged particle (+q) is released from rest at the origin. When the particle reaches a point P(x, y, z) , then it attains kinetic energy K that is equal to

Electric field strength bar(E)=E_(0)hat(i) and bar(B)=B_(0)hat(i) exists in a region. A charge is projected with a velocity bar(v)=v_(0)hat(j) at origin , then

A point charge +q_0 is projected in a magnetic field vec B= (hat i+2 hat j-3hat k) . If acceleration of the particle is vec a= ( 2hat i+b hat j-hat k) then value of b will be

If a unit vector is represented by 0.5 hat(i)-0.8 hat(j)+chat(k) , then the value of 'c' is :-

A particle is moving with speed 6m/s along the direction of 2hat(i)+2hat(j)-hat(k) find the velocity vector of a particle ?

Electric field strength bar(E)=E_(0)hat(i) and magnetic induction bar(B)=B_(0)hat(i) exists in a region. A charged particle 'q' is released from rest at origin. Work done by both the fields is after certain time is