Let P be a plane passing through the points (2,1,0) (4,1,1) and (5,0,1) and R be any point (2,1,6) . Then the image of R in the plane P is :

Let P be a plane passing through the points (2,1,0), ( lambda - 1 , 1,1) and ( lambda ,0,1) and R be any point (2,1,6) and image of R in P is Q (6,5,-2) then lambda can be (lambda in R)

Equation of the plane passing through the points (1,0,1), (-1,1,1) and (2,3,1) is

The equation of plane passing through the points (1,2,-3),(3,1,0) and (0,1,1) is

find the equation of the plane passing through points (2,1,0),(5,0,1) and (4,1,1).

Find the equation of the plane passing through the points (2,1,0),(5,0,1) and (4,1,1) If P is the point (2,1,6) then find point Q such that PQ is perpendicular to the above plane and the mid point of PQ lies on it.

vector equation of the plane passing through the points (1,-2,5),(0,-5,-1) and (-3,5,0) is

The vector equation of the plane passing through the points (1,-2,1),(2,-1,-3) and (0,1,5) is

Let P be a plane passing through the points (a,0,0),(0,b,0),(0,0,c) then the image of origin with respect to plane P is :

Find equation of plane passing through the points P(1, 1, 1), Q(3, -1, 2) and R(-3, 5, -4) .