`int_(0)^((pi)/(2))cos 2x dx`

If A=int_((rho)/(2))^((pi)/(2))cos(sin x)dxB=int_(0)^((pi)/(2))sin(cos x)dx and C=int_(0)^((pi)/(2))cos(x)dx

If A=int_(0)^( pi)(sin x)/(x^(2))dx, then int_(0)^((pi)/(2))(cos(2x))/(x)dx, is equal to:

u,=int_(0)^((pi)/(2))cos((2 pi)/(3)sin^(2)x)dx and v,=int_(0)^((pi)/(2))cos((pi)/(3)sin x)dx

If A = int_(0)^((pi)/(2))(sin^(3)x)/(1+cos^(2)s)dx and B=int_(0)^((pi)/(2))(cos^(2)x)/(1+sin^(2)x)dx , then (2A)/(B) is equal to

int_0^(pi//2) x^2 cos 2x dx

int_(0)^(pi//2)cos^(2) x" "dx=

int _(0)^(pi//2)cos^(2)x dx is equal to