Home
Class 12
PHYSICS
One of the circuits for the measurement ...

One of the circuits for the measurement of resistance by potentiometer is shown. The galvanometer is connected at point `A` and zero deflection is observed is observed at length `PJ = 30 cm`. In second case the secondary cell is changed.

Take `E_(s) = 10 V` and `r = 1 Omega` in `1^(st)` reading and `E_(s) = 5 V` and `r = 2 Omega` in `2^(nd)` reading. In second case, the zero deflection is observed at length `PJ = 10 cm`. What is the resistance `R` (in ohm)?

Promotional Banner

Similar Questions

Explore conceptually related problems

In the circuit shown, reading of the voltmeter connected across 400 Omega resistance is 60 V. If it is connected across 300 Omega resistance then reading in volt will be

A cell of e.m.f. 1.2 V is balanced by 150 cm of potentiometer wire. When the cell is shunted by a resistance of 4 Omega , the balancing length is reduced by 30 cm. What is the internal resistance of the cell ?

A potentiometer wire of length 1.0 m has a resistance of 10 Omega . It is connected to a 6 V battery in seried with a resistance of 5 Omega . Determine the emf of the primary cell which gives a balance point at 40 cm.

In the given potentiometer circuit length of the wire AB is 3 m and resistance is R = 4.5 Omega . The length AC for no deflection in galvanometer is

In the figure, the potentiometer wire of length l = 100 cm and resistance 9 Omega is joined to a cell of emf cell of emf E_(2) = 5 V and internal resistance r_(2) = 2 V is connected as shown. The galvanometer is show no deflection when the length AC is