The focal length of a mirror is given by 1/v-1/u=2/f .If equal errors alpha are made in measuring u and v .Then relative error in

The focal length of a mirror is given by (1)/(v)-(1)/(u)=(2)/(f). If equal errors alpha are made inmeasuring u and v. Then relative error in f is

The focal f to a mirror is given by (1)/(f) = (1)/(u) + (1)/(v) where u and v represent object and image distance respectively then

The mirror formula is given by 1/v+1/u=1/f where the symbols have their usual meanings. Then the lens formula is given by

A cuboid has volume V=lxx2lxx3l , where l is the length of one side. If the relative percentage error in the measurment of l is 1%, then the relative percentage error in measurement of V is

A student performed the experiment of determination of focal length of a concave mirror by u-v method using an optical bench of length 1.5 meter. The focal length of the mirror used is 24 cm. The maximum error in the location of the image can be 0.2 cm. The 5 sets of (u,v) values recorded by the student (in cm) are: (42,56),(48,48),(60,40),(66,33),(78,39) . The data set (s) that cannot come from experiment and is (are) incorrectly recorded, is (are)

The relation between u, v and f for a mirror given by:

A student measures the focal length of a convex lens by putting an object pin at a distance u from the lens and measuring the distance v of the image pin. The graph between u and v plotted by the student should look like

Assertion : The focal length of the mirrorr is f and distance of the object from the focus is u , the magnification of the mirror is f//u . Reason : Magnification =("Size of the image")/("Size of object" )

The focal length of a less is given by the formula (1)/(f)=(1)/(u)+(1)/(v) . Make f as the subject of the formula. if u=20cm and v=30, then find f. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Given (1)/(f)=(1)/(u)+(1)/(v) (B) rArr f=(uv)/(u+v) (C) f=(20xx30)/(20+30)=(600)/(50)=12 cm. (D) rArr (1)/(f)=(v+u)/(uv)