`dy/dx+y tan x= sec x`.

(dy)/(dx) + 2y tan x = sec x

What is the equation of the curve passing through the origin and satisfying the differential equation dy = (y tan x + sec x) dx ?

Solve (dy)/(dx)+y tan x=y^(2)sec x

Solve (dy)/(dx)+y tan x=y^(2)sec x

Solve (dy)/(dx)+y tan x=y^(2)sec x

Solve the following differential equation: (dy)/(dx)-y tan x=e^(x)sec x

The general solution of the differential equation (dy)/(dx) = y tan x - y^(2) sec x is

The solution of the differential equation (dy)/(dx)-y tan x=e^(x)sec x is