An aeroplane with its wings spread `10 m` is flying with speed `180 km/h` in horizontal direction. The total intensity of earth's field is `2.5 X 10^-4` Tesla and angle of dip is `60°`. Then find emf induced between the tips of the plane wings.

An air plane , with 20 m wingspread is flying at 250 ms^(-1) parallel to the earth's surface at a place whre the horizontal component of earth's magnetic field is 2 xx 10^(-5) T and angle of dip is 60^@ . The magnitude of the induced emf between the tips of the wings is

An aeroplane, in which the distance between the tips of thie wings is 50m, is flying horizontally with a speed of 360 km//hour , over a place where the vertical component of earth's magnetic field is 2.0 xx 10^(-4) tesla. The potential difference between the tips of the wings would be

A jet plane is travelling west at 450 m//s . If the horizontal component of earth's magnetic field at the place is 4 xx 10^(-4) T and the angle of dip is 30^(@) , find the e.m.f. induced between the ends of wings having a spam fo 30 m.

Horizontal component of earth at a place is 3*2xx10^-5T , and angle of dip is 60^@ . The resultant intensity of earth's field at the place is

The distance between the ends of wings of an aeroplane is 3m. This aeroplane is descending down with a speed of 300 km/hour. If the horizontal component of earths magnetic field is 0.4 gauss then the value of e.m.f. induced in the wings of the plane will be –

An aeroplane with wings span 30 m flying at 200 ms^-1 straight south parallel to earth surface. If the earth's magnetic field has a horizontal component 2 × 10^-4 Wb m^-2 and 37° dip angle, then emf induced between the tips of wings will be