Find the equation of the normal to the curve `y= x+1/x ,x gt 0` perpendicular to the line `3x - 4y =7`.

Find the equations of the normal to the curve y=4x^(3)-3x+5 , which are perpendicular to the line : 9x-y+5=0 .

The point at which the normal to the curve y = x+(1)/(x), x gt 0 is perpendicular to the line 3x – 4y – 7 = 0 is:

Find the equation of normal to the curve y=sqrt(x-3) which is perpendicular to the line 6x+ 3y-4=0

Find the equation of the normal to the curve y=2x^(3)+3 sin x" at "x=0 .

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.

Find the equation of the tangent line to the curve y=x^2-2x+7 which is perpendicular to the line 5y-15 x=13 .

Find the equation of the normals to the curve y=x^(3)+2x+6 which are parallel to the line x+14y+4=0

Find the equations of the normal to the curve y=x^(3)+2x+6 which are parallel to the line x+14y+4=0

Find the equation of a normal to the curve y=x log_(e)x which is parallel to the line 2x-2y+3=0

Find the equation of the normal to the curve 3x^2-y^2=8 which are parallel to the line x+3y-5=0