If the acceleration due to gravity at the surface of the earth is g, the work done in slowly lifting a body of mass m from the earth's surface to a height R equal to the radius of the earth is

If the acceleration due to gravity at the surface of the earth is g, the work done in slowly lifting a body ofmass m from the earth's surface to a height R equal to the radius of the earth is

What is the work done in shifting a body of mass m=5okg slowly from the earth's surface to infinity?

The acceleration due to gravity on the surface of the earth is g. If a body of mass m is raised from the surface of the earth to a height equal to the radius R of the earth, then the gain in its potential energy is given by

The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth is

The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth, is :

If g is the acceleration due to gravity on earth's surface, the gain of the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is

Find work done in shifting a body of mass m from a height h above the earth's surface to a height 2h above the earth's surface.

If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of an object of mass m raised from surface of the earth to a height equal to radius R of the earth is - [M = mass of earth]