If `1,omega,omega^(2)` are the cube roots of unity, then the roots of the equation `(x-1)^(3)+8=0` are

If the cube roots of unity are 1,ww^(2), then the roots of the equation (x-1)^(3)+8=0, are

if 1,w,w^(2) be imaginary cube root of unity then the root of equation (x-1)^(3)+8=0 are :

if 1,omega,omega^(2) root of the unity then The roots of the equation (x-1)^(3)+8=0 are

If 1,omega,omega^(2) denote the cube roots of unity,find the roots of (x+5)^(3)+27=0

If omega denotes the cube root of unity, then what is the real root of the equaton x^(3)-27=0 ?

If 1,omega,omega^(2) are the 3 cube roots of unity,then for alpha,beta,gamma,delta in R

If the cube roots of unity are 1,omega,omega^(2), then the roots of the equation (x-1)^(3)+8=0, arte

If the cube roots of unity are 1,omega,omega^(2), then the roots of the equation (x-1)^(3)+8=0 are -1,1+2 omega,1+2 omega^(2) b.-1,1-2 omega,1-2 omega^(2) c.-1,-1,-1 d.none of these

If the cube roots of unity are 1,omega,omega^(2), then the roots of the equation (x-1)^(3)+8=0 are : (a)-1,1+2w,1+2w^(2)(b)-1,1-2w,1-2w^(2)(b)1,w,w^(2)

If 1,omega,omega^(2) are cube roots of unity then 1,omega,omega^(2) are in