In a hydrogen atom,electron moves from second excited state to first excited state and then from first excited state to ground state.The ratio of wavelengths is

An electron in hydrogen atom first jumps form second excited state to first excited state and then form first excited state to ground state. Let the ratio of wavelength, momentum and energy of photons emitted in these two cases be a, b and c respectively, Then

Electron in hydrogen atom first jumps from third excited state to second excited state and then form second excited state to first excited state. The ratio of wavelength lambda_(1): lambda_(2) emitted in two cases is

When a hydrogen atom is excited from ground state to first excited state, then

When a hydrogen atom is excited from ground state to first excited state then

When an electron in hydrogen atom is taken from fourth excited state to ground state

The ratio of wavelenghts of photons emitted when hydrogen atom de-excites from third excieted state to second excited state then de-excities form second excited state to first excited state is :

The ratio of energies of hydrogen atom in its first excited state to third excited state is

In a hydrogen atom, the electron is in nth excited state. It comes down to the first excited state by emitting 10 different wavelength. The value of n is

Hydrogen atom in third excited state de-excites to the first excited state. Obtain the expressions for the frequency of radiation emitted in this process. Also determine the ratio of the wavelengths of the emitted radiations when the atom de-excites from the third excited state to the second excited state and from the third excited state to the first excited state.