A capacitor is charged to a potential difference of `100V` and then it is connected across a resistor.After one second,the potential drop across the plates of the capacitor becomes `80V` .Then after `2 sec` the potential difference

The plates of a parallel plate capacitor are charged to a potential difference of 117 V and then connected across a resistor. The potential difference across the capacitor decreases exponentially with to time.After 1s the potential difference between the plates is 39 V, then after 2s from the start, the potential difference (in V) between the plates is

The plates of a capacitor are charged to a potential difference of 320 volt and are then connected across a resistor. The potential difference across the capacitor decays exponentially with time. After 1 sec the potential difference between the plates of the capacitor is 240 volts. what is the potential difference between the plates after 2 s?

The plates of capacitor are charged to a potential difference of 100V and then connected across a resistor.When the potential difference between the plates of the capacitor is 60V ,what is the fraction of the stored energy which has been dissipated?

A capacitor is charged to a potential difference of 100 V and is then connected across a resistor. The potential difference across the capacitor decays exponentially with respect to time. After 1 sec, the P.D. between the plates of the capacitor is 80 V. what will be the potential difference between the plates after 2 sec ?

A parallel plate capacitor is charged to a potential difference of 50V. It is discharged through a resistance. After 1 second, the potential difference between plates becomes 40V. Then

In the circuit diagram find the potential difference across the plates of capacitor C