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If A=[[a,0,0] , [0,a,0] , [0,0,a]] then ...

If `A=[[a,0,0] , [0,a,0] , [0,0,a]]` then `|adj A|=`

A

`a^27`

B

`a^9`

C

`a^6`

D

`a^2`

Text Solution

Verified by Experts

Since A is a diagona matrix. Therefore,
`absA=axxa=a^3`
Also,
`abs(adjA)=abs(A)^(3-1) [:' abs(adjA)=abs(A)^(n-1)]`
`rArr abs(adjA)abs(A)^2=a^6`
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