How long a current of 3 amp has to be passed through a solution of `AgNO_(3)` to coat a metal surface of `80 cm^(2)` with 0.005 mm thick layer ? Density of Ag is `10.5 g//cm^(3)`.

Explanation

To solve the problem, we need to determine how long a current of 3 A must be passed through a solution of AgNO₃ to coat a metal surface of 80 cm² with a thickness of 0.005 mm. We will use the following steps:

### Step 1: Convert the thickness from mm to cm
The thickness of the silver layer is given as 0.005 mm. We need to convert this to centimeters for consistency with the area measurement.

\[ \text{Thickness in cm} = 0.005 \, \text{mm} \times \frac{1 \, \text{cm}}{10 \, \text{mm}} = 0.0005 \, \text{cm} \]
...