A lead storage battery has initially 200 g of holf and 200 g of `PbO_(2)`, plus excess `H_(2)SO_(4)`. Theoretically, how long could this cell deliver a current of 10 amp, without reacharging, if it were possible to operate it so that the reaction goes to completion.

Explanation

To solve the problem of how long a lead storage battery can deliver a current of 10 A with the given amounts of lead (Pb) and lead oxide (PbO₂), we need to follow these steps:

### Step 1: Determine the moles of Pb and PbO₂
- **Molar Mass of Pb**: 207.2 g/mol
- **Molar Mass of PbO₂**: 239.2 g/mol

Calculate the moles of Pb and PbO₂:
- Moles of Pb = Mass of Pb / Molar Mass of Pb = 200 g / 207.2 g/mol = 0.965 moles
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