If the wavelength of light is `5.89 xx 10^(-5)` cm, what will be the energy in one photon in the given region of light ? (`h= 6.63 xx 10^(-27) " erg".s, c= 3 xx 10^(10)cm//s`)

Explanation

We have, E= hv
and `c= v lamda`
From which we get, `E= (hc)/(lamda)`
`=(6.63 xx 10^(-27) xx 3 xx 10^(10))/(5.89 xx 10^(-5))`
`=3.37 xx 10^(-12)` erg