The first ionisation potential for Li is 5.41 eV and electron affinity of Cl is 3.61eV. Calculate `Delta H` in kJ/mol for the reaction.
`Li(g) + Cl(g) rarr Li^(+) + Cl^(-)`
Suppose that the resulting ions do not combine with each other. (1 eV= `1.60 xx 10^(-22)kJ`, Av. const.`=6.02 xx 10^(23)`)

Explanation

To calculate the change in enthalpy (ΔH) for the reaction:

\[ \text{Li(g)} + \text{Cl(g)} \rightarrow \text{Li}^+(g) + \text{Cl}^-(g) \]

we will consider the first ionization potential of lithium and the electron affinity of chlorine.

### Step 1: Understanding the Energies Involved
- The first ionization potential (IP) of lithium (Li) is the energy required to remove one electron from a neutral lithium atom to form a lithium ion (Li⁺). This value is given as 5.41 eV.
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