With what velocity should an `alpha`-particle travel towards the nucleus of a Cu atom so as to arrive at a distance `10^(-13)` metre from the nucleus of the Cu atom? `(Cu= 29, e= 1.6 xx 10^(-19)C, epsi_(0)=8.85 xx 10^(-12)J^(-1)C^(2)m^(-1), m_(e )=9.1 xx 10^(-31)kg)`

Explanation

To solve the problem, we need to calculate the velocity of an alpha particle as it approaches the nucleus of a copper atom. We will use the concept of electrostatic potential energy and kinetic energy.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Charge of an alpha particle (Z = 2, since it has 2 protons): \( q_{\alpha} = 2e = 2 \times 1.6 \times 10^{-19} \, C \)
- Charge of the copper nucleus (Z = 29): \( q_{Cu} = 29e = 29 \times 1.6 \times 10^{-19} \, C \)
- Distance from the nucleus: \( r = 10^{-13} \, m \)
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