`""^(64)Cu (t_(½)=12.8h)` decays by `beta^(-)` -emission (38%), `beta^(+)`-emission (19%) and electron capture (43%). Write decay products and calculate partial half-lives for each of the decay processes.

Explanation

`lamda_(Cu)= (0.6932)/(12.8)= 0.054`

`therefore lamda_(1)` = fractional yield of `Zn xx lamda_(Cu)= (38)/(100) xx 0.054 = 0.0205`
`therefore t_(½)` for `beta^(-)` emission `=(0.6932)/(0.0205)= 33.8h`
Similarly we can calculate, `t_(½)` for `beta^(+)` emission = 67.6h and `t_(½)` for electron capture= 29.85h