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The ratio of energy of a photon of 2000Å...

The ratio of energy of a photon of `2000Å` wavelength radiation to that of `4000Å` radiation is

A

`1//4`

B

4

C

`1//2`

D

2

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The correct Answer is:
To find the ratio of the energy of a photon with a wavelength of 2000 Å to that of a photon with a wavelength of 4000 Å, we can follow these steps: ### Step 1: Understand the formula for energy of a photon The energy (E) of a photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] where: - \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{Js} \)), - \( c \) is the speed of light (\( 3 \times 10^8 \, \text{m/s} \)), - \( \lambda \) is the wavelength of the radiation. ### Step 2: Calculate the energy for the photon with wavelength 4000 Å Convert the wavelength from angstroms to meters: \[ 4000 \, \text{Å} = 4000 \times 10^{-10} \, \text{m} = 4 \times 10^{-7} \, \text{m} \] Now, substitute the values into the energy formula: \[ E_1 = \frac{hc}{\lambda_1} = \frac{hc}{4 \times 10^{-7}} \] ### Step 3: Calculate the energy for the photon with wavelength 2000 Å Convert the wavelength from angstroms to meters: \[ 2000 \, \text{Å} = 2000 \times 10^{-10} \, \text{m} = 2 \times 10^{-7} \, \text{m} \] Now, substitute the values into the energy formula: \[ E_2 = \frac{hc}{\lambda_2} = \frac{hc}{2 \times 10^{-7}} \] ### Step 4: Find the ratio of the energies Now we can find the ratio of the energies \( E_1 \) to \( E_2 \): \[ \frac{E_1}{E_2} = \frac{\frac{hc}{4 \times 10^{-7}}}{\frac{hc}{2 \times 10^{-7}}} \] ### Step 5: Simplify the ratio The \( hc \) terms cancel out: \[ \frac{E_1}{E_2} = \frac{1}{4 \times 10^{-7}} \times \frac{2 \times 10^{-7}}{1} = \frac{2}{4} = \frac{1}{2} \] ### Conclusion Thus, the ratio of the energy of a photon of 2000 Å wavelength radiation to that of 4000 Å radiation is: \[ \frac{E_1}{E_2} = \frac{1}{2} \]
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