The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_(0)` is Bohr radius] :

Options

A. `(h^(2))/(4pi^(2)ma_(0)^(2))`
B. `(h^(2))/(16pi^(2) ma_(0)^(2))`
C. `(h^(2))/(32pi^(2) ma_(0)^(2))`
D. `(h^(2))/(64pi^(2) ma_(0)^(2))`

Answer

C

Explanation

`mvr= (nh)/(2pi), mv= (nh)/(2pi r) and KE = (1)/(2)mv^(2)= (m^(2)v^(2))/(2m) or E= (n^(2)h^(2))/(4pi^(2) r^(2))xx (1)/(2m)`
use `r= n^(2) a_(0) (a_(0)=r_(1))`