Calculate `Delta_(r )H` for the following homogeous gaseous reaction :
`CH_(3)COCH_(3)(g)+2O_(2)(g)rarr CH_(3)COOH(g)+CO_(2)(g)+H_(2)O(g)`
Use the data in kcal `mol^(-1)`.
`Delta_("bond C-H")=99 , Delta_("bond C - C")=83 , Delta_("bond C = O")=173` ,
`Detla+("bond O = O")=118 , Delta_("bond C - O")=84 , Delta_("bond O - H")=110`

Explanation

We have
`H-overset(H)overset(|)underset(H)underset(|)(C )-overset(O)overset(||)(C )-overset(H)overset(|)underset(H)underset(|)(C )-H+2O=O to H-overset(H)overset(|)underset(H)underset(|)(C )-overset(O)overset(||)(C )-O-H+O=C=O`
`+H-O-H`, `DeltaH=?`
For reactants
Bond energy of 6 moles of C-H bonds `=6xx99` kcal
Bond energy of 2 moles of C-C bonds `=2xx83` kcal
Bond energy of 1 mole of `C=O` bonds `=1xx173` kcal
Bond energy of 2 moles of O=O bonds `=2xx118` kcal
For products
Energy of formation of 3 moles of C-H bonds `=-3xx99` kcal
Energy of formation of 1 mole of C-C bonds `=-83` kcal
Energy of formation of 1 mole of C=O bonds `=-173` kcal
Energy of formation of 1 mole of C-O bonds `=-84` kcal
Energy of formation of 1 mole of O-H bonds `=-110` kcal
Energy of formation of 2 moles of C=O bonds `=-2xx173` kcal
Energy of formation of 2 moles of O-H bonds `=-2xx110` kcal
Adding up, we get `DeltaH` of the required equation i.e.,
`DeltaH=-144` kcal