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For the reaction, C("graphite")+(1)/(2)O...

For the reaction, `C_("graphite")+(1)/(2)O_(2)(g)=CO(g)` at 298 K and 1 atm, DeltaH=-26416 cal. If the molar volume of graphite is 0.0053 litre, calculate DeltaH.

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The correct Answer is:
(-26712 cal)
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