Calculate heat of formation of `KOH(s)` using the following equations
`K(s) +H_(2)O(l) +aq rarr KOH(aq)+1//2 H_(2)(g),DeltaH =- 48.0 kcal …(i)`
`H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l),DeltaH =- 68.4 kcal …(ii)`
`KOH(s) +(aq) rarr KOH(aq),DeltaH =- 14.0 kcal ....(iii)`

Answer

(-102.46 kcal)