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The heat of combustion of graphite at 29...

The heat of combustion of graphite at 298 K is -393.795 kJ/mole, while that of diamond's combustion at the same temperature is -395.692 kJ/mole. The specific heats for these substances are 720.83 and 505.58 `J kg^(-1)K^(-1)` respectively. Calculate the heat of graphite's transformation into diamond at 273 K.

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Verified by Experts

The correct Answer is:
`(2.0645 "kJ mole"^(-1))`
`DeltaH={-393-(395)}+(0.720-0.505)xx(12)/(1000)xx(298-273)]`
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