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Calculate the resonance energy of N(2)O ...

Calculate the resonance energy of `N_(2)O` from the following data :
`DeltaH_(f)^(@)` of `N_(2)O = 82 kJ mol^(-1)`, Bond energies of `N equivN`, `N = N , O =O and N =O` bonds are 946, 418, 498 and 607 `kJ mol^(-1)` respectively.

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The correct Answer is:
(-88 kJ)
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Calculate the resonance enegry of N_(2)O form the following data Delta_(f)H^(Theta) of N_(2)O = 82 kJ mol^(-1) Bond enegry of N-=N, N=N, O=O, and N=O bond is 946, 418, 498 , and 607 kJ mol^(-1) , respectively.

Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mol"^(-1)

Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mole"^(-1)

Calculate the resonance enegry of NO_(2) ( :O-N=O: ) The measured enthalpy formation of NO_(2)(Delta_(f)H^(Theta)) is 34 kJ mol^(-1) . The bond energies given are: N -O rArr 222 kJ mol^(-1) N -= N rArr 946 kJ mol^(-1) O = O rArr 498 kJ mol^(-1) N = O rArr 607 kJ mol^(-1)

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