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One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.01, 95K)`to`(4.0 atm, 5.01, 245K) with a change in internal energy, `DeltaU=30.0L` atm. The change in enthalpy `DeltaH` of the process in L atm is.

A

`40.0`

B

`42.3`

C

`44.0`

D

not defined , because pressure is not constant

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaH=Deltau+(p_(2)V_(2)-p_(1)V_(1))`
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