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Given (i) 2Fe(2)O(3)(s) rarr 4Fe(s)+3...

Given
(i) `2Fe_(2)O_(3)(s) rarr 4Fe(s)+3O_(2)(g)`,
`DeltaG^(@)=+1487.0 kj mol^(-1)`
(ii) `2CI(g)+O_(2) rarr 2CO_(2)(g)`,
`Delta_(r )G^(@)=-514.4 kj mol^(-1)`
Free energy change `Delta_(r)G^(@)` for the reaction
`2Fe_(2)O_(3)(s)+6CO(g) rarr 4Fe(s)+6cO_(2)(g)` will be :

A

`-168.2 "kJ mol"^(-1)`

B

`-208.0 "kJ mol^(-1)`

C

`56.2 "kJ mol^(-1)`

D

`-112.4 "kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Cal. `DeltaG^(@) following [eqn. (i) +3 eqn. (ii)`
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