Balance the following equations by oxidation number method.
`KMnO_(4)+H_(3)AsO_(3)+HCl toKCl+MnCl_(2)+H_(3)AsO_(4)+H_(2)O`

Explanation

`3 xx 55.85 g , 3 xx 6.022 xx 10^(23) "atoms"(3Fe) + underset("4 moles" 4 xx 18.016 g 4 xx 6.022 xx 10^(23) "molecules")(4H_(2)O) to underset("one mole" 231.55 g, 6.022 xx 10^(23) "molecules")(Fe_(3)O_(4)) + underset("4 moles" 4 xx 22.4 L "at S.T.P.") (4 xx 6.022 xx 10^(23) "molecules")`