Normality of a '30 volume `H_2O_2`' solution is:

Options

A. 1.6
B. 91.07
C. 10.72
D. 5.36

Explanation

To find the normality of a '30 volume H₂O₂' solution, we can use the relationship between volume strength and normality. Here’s a step-by-step solution:

### Step 1: Understand the relationship
The formula that relates volume strength (VS) to normality (N) is:
\[ \text{Volume Strength} = 5.6 \times \text{Normality} \]
Where:
- Volume Strength (VS) is given in the question as 30.
- Normality (N) is what we need to find.

### Step 2: Substitute the known values
From the question, we know:
\[ \text{Volume Strength} = 30 \]
So we can substitute this into the formula:
\[ 30 = 5.6 \times N \]

### Step 3: Solve for Normality (N)
To find N, we rearrange the equation:
\[ N = \frac{30}{5.6} \]

### Step 4: Calculate the value
Now, we perform the division:
\[ N = \frac{30}{5.6} \approx 5.36 \]

### Conclusion
The normality of the '30 volume H₂O₂' solution is approximately **5.36**.