How many moles of magnesium phosphate `Mg_3 (PO_4)_2` will contain 0.25 mole of oxygen atoms ?

Options

A. (a) `0.02`
B. (b) `3.125 xx 10^(-2)`
C. (c) `1.25 xx 10^(-2)`
D. (d) `2.5 xx 10^(-2)`

Answer

B

Explanation

From the formula, `Mg_3(PO_4)_2`, it .s clear that 8 moles of oxygen atoms are present in 1 mole of magnesium phosphate.
`therefore` 0.25 moles of oxygen atoms will be present in`1/8 xx 0.25 = 3.125 xx 10^(-2)` moles of `Mg_(3)(PO_(4))_(2)`.