One mole of `K_2SO_4` contains `5.02 xx 10^(23)` potassium ions.

Answer

To solve the question, we need to determine how many potassium ions are present in one mole of potassium sulfate (K₂SO₄).

### Step-by-Step Solution:

1. **Understanding the Composition of K₂SO₄**:
- The chemical formula K₂SO₄ indicates that there are 2 potassium (K) ions for every formula unit of K₂SO₄.

2. **Using Avogadro's Number**:
- One mole of any substance contains Avogadro's number of entities, which is approximately \(6.022 \times 10^{23}\).
- Therefore, one mole of K₂SO₄ contains \(6.022 \times 10^{23}\) molecules of K₂SO₄.

3. **Calculating the Number of Potassium Ions**:
- Since each molecule of K₂SO₄ contains 2 potassium ions, the total number of potassium ions in one mole of K₂SO₄ can be calculated as follows:
\[ \text{Number of K ions} = \text{Number of K₂SO₄ molecules} \times 2 \]
\[ \text{Number of K ions} = (6.022 \times 10^{23}) \times 2 \]
\[ \text{Number of K ions} = 12.044 \times 10^{23} \]

4. **Conclusion**:
- Therefore, one mole of K₂SO₄ contains \(12.044 \times 10^{23}\) potassium ions.

### Final Answer:
One mole of K₂SO₄ contains \(12.044 \times 10^{23}\) potassium ions.

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