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Total number of atoms in 90 g of water a...

Total number of atoms in 90 g of water are.........

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To find the total number of atoms in 90 g of water (H₂O), we can follow these steps: ### Step 1: Determine the molecular formula of water Water has the molecular formula H₂O, which means each molecule of water contains: - 2 hydrogen (H) atoms - 1 oxygen (O) atom Thus, each molecule of water contains a total of: \[ 2 \text{ H atoms} + 1 \text{ O atom} = 3 \text{ atoms} \] ### Step 2: Calculate the molar mass of water The molar mass of water can be calculated as follows: - Hydrogen (H) has an atomic mass of approximately 1 g/mol. Since there are 2 hydrogen atoms: \[ 2 \times 1 = 2 \text{ g/mol} \] - Oxygen (O) has an atomic mass of approximately 16 g/mol. Therefore: \[ 1 \times 16 = 16 \text{ g/mol} \] - Adding these together gives the molar mass of water: \[ 2 \text{ g/mol} + 16 \text{ g/mol} = 18 \text{ g/mol} \] ### Step 3: Calculate the number of moles of water in 90 g We can calculate the number of moles of water using the formula: \[ \text{Moles of water} = \frac{\text{mass of water (g)}}{\text{molar mass of water (g/mol)}} \] Substituting the values: \[ \text{Moles of water} = \frac{90 \text{ g}}{18 \text{ g/mol}} = 5 \text{ moles} \] ### Step 4: Calculate the total number of atoms Since we know that 1 mole of water contains 3 moles of atoms, we can calculate the total number of moles of atoms in 5 moles of water: \[ \text{Total moles of atoms} = 5 \text{ moles of water} \times 3 \text{ moles of atoms/mole of water} = 15 \text{ moles of atoms} \] ### Step 5: Convert moles of atoms to number of atoms To find the total number of atoms, we use Avogadro's number, which is approximately \( 6.02 \times 10^{23} \) atoms/mole: \[ \text{Total number of atoms} = 15 \text{ moles of atoms} \times 6.02 \times 10^{23} \text{ atoms/mole} \] Calculating this gives: \[ \text{Total number of atoms} = 15 \times 6.02 \times 10^{23} \approx 9.03 \times 10^{24} \text{ atoms} \] ### Final Answer The total number of atoms in 90 g of water is approximately \( 9.03 \times 10^{24} \) atoms. ---
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Knowledge Check

  • Total number of atoms present in 34 g of NH_3 is

    A
    `4xx10^23`
    B
    `4.8xx10^21`
    C
    `2xx10^23`
    D
    `48xx10^23`
  • The total number of electrons present in 18 mL of water (density of water is 1 g mL^(-1) is:

    A
    `6.02 xx 10^(23)`
    B
    `6.02 xx 10^(22)`
    C
    `6.02 xx 10^(24)`
    D
    `6.02 xx 10^(25)`
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