The volume occupied by 64 g of `SO_2` at S.T.P. is……………..

Answer

To find the volume occupied by 64 g of SO₂ at Standard Temperature and Pressure (STP), we can follow these steps:

### Step 1: Determine the molar mass of SO₂
The molar mass of sulfur dioxide (SO₂) can be calculated as follows:
- Sulfur (S) has a molar mass of approximately 32 g/mol.
- Oxygen (O) has a molar mass of approximately 16 g/mol.
- Therefore, the molar mass of SO₂ = 32 g/mol (for S) + 2 × 16 g/mol (for O) = 32 + 32 = 64 g/mol.

### Step 2: Calculate the number of moles of SO₂
Using the formula for moles:
\[ \text{Moles} = \frac{\text{Mass (g)}}{\text{Molar Mass (g/mol)}} \]
Substituting the values:
\[ \text{Moles of SO₂} = \frac{64 \text{ g}}{64 \text{ g/mol}} = 1 \text{ mole} \]

### Step 3: Use the molar volume at STP to find the volume
At STP, 1 mole of any ideal gas occupies a volume of 22.4 liters. Therefore, the volume occupied by 1 mole of SO₂ is:
\[ \text{Volume} = \text{Moles} \times \text{Molar Volume} \]
Substituting the values:
\[ \text{Volume of SO₂} = 1 \text{ mole} \times 22.4 \text{ L/mole} = 22.4 \text{ liters} \]

### Final Answer
The volume occupied by 64 g of SO₂ at STP is **22.4 liters**.

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