If the speed of light is `3.0 xx 108 m s^(–1)`, calculate the distance covered by light in 2.00 ns.

Explanation

Distance covered = speed `xx` time
`=3.0 xx 10^(8) ms^(-1) xx 2.00 s`
`=3.0 xx 10^(80) ms^(-1) xx 2.00 ns xx (10^(-9) s)/(1 ns)=6.00 xx 10^(-1) m = 0.600 m`