4 g of `O_2` and 2g of `H_2` are confined in a vessel of capacity 1 litre at `0^@C`. Calculate
the partial pressure of each gas, and

Explanation

Calculation of partial pressures :
Volume of vessel = 1 L, `T = 0^@C = 273 K`
`:. " " PV = nRT " or " p = (nRT)/V`
`:.` Partial pressure of oxygen
`Po_2=(nRT)/V =( 0.125 xx 0.0821 xx 273)/1 = 2.80` atm
Similarly, partial pressure of hydrogen
`P_(H_2)= (nRT)/V= (1xx0.0821 xx 273)/1 = 22.4` atm