The volume of a gas X and chlorine diffusing during the same time are 35 mL and 29 mL respectively. If molecular mass of chlorine is 71, calculate the molecular mass of gas X.

Explanation

Suppose the molecular weight of the gas X is `M_1` . According to Eq. 5.25, we have
`V_1/V_2 = sqrt(M_2/M_1) " " (t_2 and t_2` being the same)
In the present case,
`V_1 = 35 mL, V_2 = 29 mL, M_1 = ? " and " M_2 = 71`
`:. 35/29 sqrt(71/M_1) " or " M_1 = 48.74`
`:.` The Molecular weight of the gas `X =48.74`.