What weight of AgCl would be precipitated if 10 mL of HCl gas measured at `12^@C` and 750 mm pressure were passed into the excess of a solution of silver nitrate ?

Explanation

To find the weight of AgCl precipitated when 10 mL of HCl gas is passed into an excess of silver nitrate solution, we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between silver nitrate (AgNO3) and hydrochloric acid (HCl) is:
\[ \text{AgNO}_3 + \text{HCl} \rightarrow \text{AgCl} + \text{HNO}_3 \]

From this equation, we can see that 1 mole of HCl reacts to produce 1 mole of AgCl.

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